• Try to solve this math puzzle for “Coke, Burger, Fries.”
• This arithmetic problem is exclusively for geniuses.
• You must be a genius to figure out the value in under 20 seconds.

Try to solve this math riddle for “Coke, Burger, Fries.” This arithmetic problem is exclusively for geniuses. The internet has been stumped by this arithmetic puzzle, which undoubtedly appears as appetizing as a McDonald’s burger, fries, and soda combo.

To answer this math conundrum, several people attempted to determine the cost of each hamburger, side of fries, and soda. You must be a genius to figure out the value in under 20 seconds. Have fun answering these arithmetic puzzles, and reward yourself with a combo of burger, fries, and drink if you get the right answer.

Only High IQ Genius Should Solve Math Puzzles!

Math Puzzles with Solutions: Solution

Row 1: There are three coke glasses or 30 total.

Therefore, if we divide both sides (LHS and RHS) by 3, the result is that the value of one Coca-Cola is equal to 10. In order to solve the problem’s following row, we will now use the value of 1 Coca-Cola. To better understand, refer to the image below.

Row 2: We now have 1 coke + 1 burger + 1 burger, which is 20. We apply the value and resolve the equation to determine the value of 1 burger since we already know that 1 coke = 10. To better understand, refer to the image below.

We now know that one hamburger is worth five dollars. Let’s assess the worth of fries.

Row 3: We now have one hamburger plus three pairs of fries, for a total of nine.

We already know that one hamburger costs five dollars. Therefore, we solve the equation using the value of 1 burger to determine the value of 1 Fries. To better understand, refer to the image below.

Row 4: The answer is 1 hamburger plus 1 single package of fries and 1 can of soda.

After determining the values of each component in our prior equations, we will now apply the values to determine the solution.

=> 1 hamburger plus 1 single-pack of fries and 1 can of coke equals??

=> 5 + 1 x 10 = ??

BODMAS application (Bracket, Of, Division, Multiplication, Addition, and Subtraction)

=> 5 + 10 = 15

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